$Xe{F}_4$ যৌগে মুক্ত ইলেকট্রন কত জোড়া?

The answer is 14 because Xenon (Xe) in the molecule XeF4 has 8 valence electrons. In addition to these, there are 4 fluorine (F) atoms, each contributing 1 electron, which leads to the formation of 4 bonds. This means that after bonding, there are 2 lone pairs left on the xenon atom.

To summarize:

    
• Xenon has 8 valence electrons.
    
• There are 4 fluorine atoms contributing 4 electrons.
    
• After forming bonds, 2 electrons remain as lone pairs on xenon.
    
• This results in a total of 14 electrons (8 from Xe and 4 from F) that are not involved in bonding.

Thus, the total count of free (or lone) electron pairs in XeF4 is 14.

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